(PHP 4, PHP 5)

func_get_args --  Returns an array comprising a function's argument list


array func_get_args ( void )

Returns an array in which each element is a copy of the corresponding member of the current user-defined function's argument list. func_get_args() will generate a warning if called from outside of a function definition. This function cannot be used directly as a function parameter. Instead, its result may be assigned to a variable, which can then be passed to the function.

Note: This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.

Note: Because this function depends on the current scope to determine parameter details, it cannot be used as a function parameter. If you must pass this value, assign the results to a variable, and pass the variable.

function foo()
$numargs = func_num_args();
"Number of arguments: $numargs<br />\n";
    if (
$numargs >= 2) {
"Second argument is: " . func_get_arg(1) . "<br />\n";
$arg_list = func_get_args();
    for (
$i = 0; $i < $numargs; $i++) {
"Argument $i is: " . $arg_list[$i] . "<br />\n";

foo(1, 2, 3);

func_get_args() may be used in conjunction with func_num_args() and func_get_arg() to allow user-defined functions to accept variable-length argument lists.